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Proof step 2 from proof div-le-same (previous step)

0 < i, 0 < j ⊦ i ≤ i / j ↔ j = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
0 < j, 0 < i, 0 < i / j, i ≤ i / j ⊦ j = 1

Rule argument

Additional information

Used simplifier rules: one: ⊦ i / 1 = i;%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs% ⊦ i ≤ i; (s)