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Proof step 3 from proof div-ls-02 (previous step)

j / j0 < i / j0, 0 < j0, i ≤ j, 0 ≤ i, 0 ≤ j ⊦

User applied rule insert lemma

And obtained the following new goals

Proof step 4:
0 < j0, 0 ≤ i, i ≤ j ⊦ i / j0 ≤ j / j0

Rule argument

spec: <toplevel> name: ls-03 seq: 0 < j0, 0 ≤ i, i ≤ j ⊦ i / j0 ≤ j / j0 subst: [j0, i, j] → [j0, i, j]

Additional information

Used simplifier rules: ⊦ i < j → (j ≤ i ↔ false); (as) Used terms: j0, i, j