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Proof step 3 from proof div-ls-mone (previous step)

0 < j ⊦ i / j < ~1 ↔ i + 2 * j ≤ 0

User applied rule cut formula

And obtained the following new goals

Proof step 4:
0 < j, i < 0 ⊦ i / j < ~1 ↔ i + 2 * j ≤ 0
Proof step 23:
0 < j ⊦ i / j < ~1 ↔ i + 2 * j ≤ 0, i < 0

Rule argument

fma: i < 0

Additional information

Used formulas: i < 0