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Proof step 15 from proof div-ls-same (previous step)

0 < j, i0 < 0, 1 < j, abs(j0) < j, i0 < j, j0 < j, i0 ≤ i0 * j + j0, j0 ≤ 0 ⊦ j = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 16:
⊦ i < j ↔ ¬ j ≤ i
Proof step 17:
j0 < j, i0 < j, abs(j0) < j, i0 < 0, 0 < j, j0 ≤ 0, i0 ≤ i0 * j + j0 ⊦ j = 1, j ≤ 1

Rule argument

spec: int-abs name: lels seq: ⊦ i < j ↔ ¬ j ≤ i subst: [j, i] → [j, 1] flags: <all paths>

Additional information

Used terms: j, 1