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Proof step 4 from proof div-ls-same (previous step)

0 < j, i < 0 ⊦ i < i / j ↔ i < 0 ∧ 1 < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
0 < j, i < 0 ⊦ i < i / j ↔ 1 < j

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i < 0 ∧ 0 ≤ j → i < j; (s)