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Proof step 9 from proof div-ls-same (previous step)

i0 * j + j0 < 0, j0 < j, i0 < j, 0 < j, abs(j0) < j, 1 < j, j0 ≤ 0, i0 ≤ 0 ⊦ i0 * j + j0 < i0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 10:
⊦ i < j ↔ ¬ j ≤ i
Proof step 11:
1 < j, abs(j0) < j, 0 < j, i0 < j, j0 < j, i0 * j + j0 < 0, i0 ≤ i0 * j + j0, i0 ≤ 0, j0 ≤ 0 ⊦

Rule argument

spec: int-abs name: lels seq: ⊦ i < j ↔ ¬ j ≤ i subst: [j, i] → [i0, i0 * j + j0] flags: <all paths>

Additional information

Used terms: i0, i0 * j + j0