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Proof step 16 from proof div-ls-zero (previous step)

0 < j ⊦ i / j < 0 ↔ i + j ≤ 0, i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
0 < j, 0 ≤ i ⊦ i / j < 0 ↔ i + j ≤ 0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs% ⊦ i < j ↔ ¬ j ≤ i; (ss)