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Proof step 1 from proof div-ls (conclusion)

j0 ≤ i / j, i < i0, i0 % j = 0, 0 < j, 0 ≤ i ⊦ j0 < i0 / j

System applied rule normalize

And obtained the following new goals

Proof step 2:
i0 % j = 0, 0 < j, i < i0, 0 ≤ i, j0 ≤ i / j ⊦ j0 < i0 / j

Rule argument

Additional information