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Proof step 7 from proof div-minus-onediff-01 (previous step)

j0 * j + 1 = i0 + j, 0 < j, j0 < 0 ⊦ i0 / j = j0, j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 8:
j0 * j + 1 = i0 + j, i0 = (j0 - 1) * j + 1, j0 < 0, 0 < j ⊦ i0 / j = j0, j = 0
Proof step 23:
j0 * j + 1 = i0 + j, j0 < 0, 0 < j ⊦ i0 / j = j0, i0 = (j0 - 1) * j + 1, j = 0

Rule argument

fma: i0 = (j0 - 1) * j + 1

Additional information

Used formulas: i0 = (j0 - 1) * j + 1