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Proof step 2 from proof div-minus255-256-01 (previous step)

i % 256 = 0, i < 0 ⊦ (i - 255) / 256 = i / 256

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i % 256 = 0, i < 0 ⊦ (i - 255) / 256 = i / 256

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs