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Proof step 20 from proof div-mult-01 (previous step)

0 < i0 ⊦ (i * i0) / (j * i0) = i / j, j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 21:
0 < i0, i < 0 ⊦ (i * i0) / (j * i0) = i / j, j = 0
Proof step 29:
0 < i0 ⊦ (i * i0) / (j * i0) = i / j, j = 0, i < 0

Rule argument

fma: i < 0

Additional information

Used formulas: i < 0