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Proof step 22 from proof div-mult-01 (previous step)

0 < i0, i < 0 ⊦ (i * i0) / (j * i0) = i / j, j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 23:
i < 0, 0 < i0, j < 0 ⊦ (i * i0) / (j * i0) = i / j, j = 0
Proof step 26:
i < 0, 0 < i0 ⊦ (i * i0) / (j * i0) = i / j, j = 0, j < 0

Rule argument

fma: j < 0

Additional information

Used formulas: j < 0