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Proof step 2 from proof div-mult-le (previous step)

0 < j, 0 ≤ i, 0 ≤ i0 ⊦ i * i0 / j ≤ (i * i0) / j

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: div-mult-ls: ⊦ 0 ≤ i ∧ 0 ≤ i0 ∧ 0 < j → ¬ (i * i0) / j < i * i0 / j;%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult% ⊦ i ≤ j ↔ ¬ j < i; (ss)