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Proof step 2 from proof div-mult-ls-pos (previous step)

0 < j, 0 ≤ i ⊦ i % j = 0, i / j * j < i

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: div-mult-le-01: ⊦ 0 ≤ i ∧ 0 < j → (i ≤ j * i / j ↔ i % j = 0);%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult% ⊦ i < j ↔ ¬ j ≤ i; (ss)