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Proof step 2 from proof div-mult-three-nls (previous step)

(j * j * j) / 3 < j, 2 ≤ j ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
(j * j * j) / 3 < j, 0 < j, 2 ≤ j, 0 ≤ j ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs