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Proof step 2 from proof div-mult-two-nls (previous step)

(2 * i) / j < 2 * i / j, 0 < j, 0 ≤ i ⊦

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: div-mult-ls: ⊦ 0 ≤ i ∧ 0 ≤ i0 ∧ 0 < j → ¬ (i * i0) / j < i * i0 / j;%commutativity: ⊦ i * j = j * i; from specification int-mult%associativity: ⊦ i * j * j0 = (i * j) * j0; from specification int-mult