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Proof step 17 from proof div-nearer-zero (previous step)

i < 0, i / abs(j) * abs(j) < i ⊦ j = 0, j < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
i < 0, i / j * j < i, 0 < j ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i < j → ¬ j < i; (s)% ⊦ ¬ j < 0 → abs(j) = j; (s)% ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)