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Proof step 5 from proof div-same (previous step)

⊦ i / i = 1, i = 0, 0 < i ∧ i ≤ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
i < 0 ⊦ i / i = 1

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i < j → ¬ j < i; (s)% ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)% ⊦ i ≤ i; (s)