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Proof step 1 from proof div-shift-two (conclusion)
i0 = (i / 2) / j * 2, j ≠ 0, 0 ≤ i, 0 ≤ j ⊦ i / j = i0 + (i - j * i0 < j ⊃ 0;1)
System applied rule normalize
And obtained the following new goals
Proof step 2
:
i0 = (i / 2) / j * 2, 0 ≤ j, 0 ≤ i ⊦ i / j = i0 + (i - j * i0 < j ⊃ 0;1), j = 0
Rule argument
Additional information