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Proof step 3 from proof div-sub-01 (previous step)

i % j = 0, i0 % j = 0 ⊦ i / j = (i - i0) / j + i0 / j, j = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
j ≠ 0 ⊦ i % j = 0 ↔ (∃ j0. i = j0 * j)
Proof step 5:
i0 % j = 0, ∃ j0. i = j0 * j ⊦ i / j = (i - i0) / j + i0 / j, j = 0

Rule argument

spec: <toplevel> name: modex seq: j ≠ 0 ⊦ i % j = 0 ↔ (∃ j0. i = j0 * j) subst: [j, i] → [j, i] flags: <all paths>

Additional information

Used terms: j, i