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Proof step 1 from proof div-sum-ls-01 (conclusion)
⊦ 0 < i ∧ 0 < i1 ∧ 0 < j1 ∧ 0 < j2 ∧ 0 < j ∧ j1 < j ∧ j2 < j → (i * j1 + i1 * j2) / j < i + i1
System applied rule normalize
And obtained the following new goals
Proof step 2
:
0 < i, 0 < i1, 0 < j1, 0 < j2, 0 < j, j1 < j, j2 < j ⊦ (i * j1 + i1 * j2) / j < i + i1
Rule argument
Additional information