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Proof step 24 from proof div-two-intro (previous step)

i0 ≤ 0 ⊦ (i0 * 2 - 1) / (j0 * 2) = i0 / j0, j0 = 0, i0 < 0 ∧ j0 < 0, i0 < 0 ∧ 0 < j0

User applied rule cut formula

And obtained the following new goals

Proof step 25:
i0 = 0, i0 ≤ 0 ⊦ (i0 * 2 - 1) / (j0 * 2) = i0 / j0, j0 = 0, i0 < 0 ∧ 0 < j0, i0 < 0 ∧ j0 < 0

Rule argument

fma: i0 = 0

Additional information

Used simplifier rules: ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)% ⊦ i < 0 ∧ 0 ≤ j → i < j; (s)% ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)% ⊦ i < j → ¬ j < i; (s) Used formulas: i0 = 0