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Proof step 2 from proof div-zero-04 (previous step)

0 < i, i < j, 0 < j ⊦ i / j = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: div-eq-zero: ⊦ 0 < i ∧ 0 < j → (i / j = 0 ↔ i < j);% ⊦ i < j → (j ≤ i ↔ false); (as)% ⊦ i < j ↔ ¬ j ≤ i; (ss)