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Proof step 6 from proof div2-nle-02 (previous step)

i + j = i0 * 2 + j0, j0 < 2, 0 < j, i < j, i < i0, 0 < i0, j ≤ i0, 0 ≤ i, 0 ≤ i + j, 0 ≤ i0, 0 ≤ j0 ⊦

User applied rule cut formula

And obtained the following new goals

Proof step 7:
i + j = i0 * 2 + j0, j0 = 1, 0 < i0, i < i0, i < j, 0 < j, j0 < 2, 0 ≤ j0, 0 ≤ i0, 0 ≤ i + j, 0 ≤ i, j ≤ i0 ⊦
Proof step 9:
i + j = i0 * 2 + j0, 0 < i0, i < i0, i < j, 0 < j, j0 < 2, 0 ≤ j0, 0 ≤ i0, 0 ≤ i + j, 0 ≤ i, j ≤ i0 ⊦ j0 = 1

Rule argument

fma: j0 = 1

Additional information

Used formulas: j0 = 1