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Proof step 8 from proof div2-nls-02 (previous step)

i + j = i0 * 2 + j0, i + j < 0, i0 < j, i0 < i, abs(j0) < 2, 0 < 2, i ≤ j, j0 ≤ 0, i0 ≤ 0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
i + j = i0 * 2 + j0, abs(j0) < 2, i0 < i, i + j < 0, i0 < j, i ≤ j, i0 ≤ 0, j0 ≤ 0 ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-04: ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs