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Proof step 2 from proof div2-odd-01 (previous step)

i < 0 ⊦ (1 - i * 2) / 2 = ~ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i < 0 ⊦ i + (1 - i * 2) / 2 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ ~ i = j ↔ i + j = 0; (s)