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Proof step 28 from proof le-abs-numerator (previous step)

abs(i) + abs(i) / j < 0, 0 < j, abs(i) / j * j ≤ abs(i) ⊦ i = 0, j = 0, 0 ≤ abs(i) ∧ 0 ≤ abs(i) / j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 29:
0 < j, abs(i) + abs(i) / j < 0, abs(i) / j < 0, abs(i) / j * j ≤ abs(i) ⊦ i = 0, j = 0

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ 0 ≤ abs(i); (s)