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Proof step 2 from proof less-mult-div-01 (previous step)

0 < i, 0 < j, 0 < j1, i1 < j ⊦ (i * i1) / j < i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i1 < j, 0 < j1, 0 < j, 0 < i, 0 < (i * i1) / j, i ≤ (i * i1) / j ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs%forward-le: ⊦ i ≤ j ∧ 0 < i → 0 < j; (forward) from specification int-abs% ⊦ i < j ↔ ¬ j ≤ i; (ss)