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Proof step 2 from proof ls-01 (previous step)

i0 ≤ j0, i ≤ j, 0 ≤ i0, 0 ≤ i ⊦ i0 = 0, j0 = 0, i / j0 ≤ j / i0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
j / i0 < i / j0, 0 < j0, 0 < i0, i ≤ j, i0 ≤ j0, 0 ≤ j, 0 ≤ i ⊦ i0 = 0, j0 = 0

Rule argument

Additional information

Used simplifier rules: forward-lele: ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward) from specification int-abs%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)