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Proof step 2 from proof ls-02 (previous step)

i / i0 < j / i0, 0 < i0 ⊦ i < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i / i0 < j / i0, 0 < i0, j ≤ i ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i < j ↔ ¬ j ≤ i; (ss)