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Proof step 16 from proof ls-even-01 (previous step)

j % 2 = 0, i % 2 = 0, i < 0 ⊦ i / 2 < j / 2 ↔ ¬ j ≤ i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
i % 2 = 0, j % 2 = 0, i < 0 ⊦ i / 2 < j / 2 ↔ ¬ j ≤ i

Rule argument

Additional information

Used simplifier rules: forward-le-02: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward) from specification int-abs