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Proof step 23 from proof ls-even-01 (previous step)

i % 2 = 0, j % 2 = 0, i < 0, 0 ≤ j → (0 < j / 2 + i / 2 ↔ 0 < j + i), j ≤ 0 → (j / 2 < i / 2 ↔ j < i) ⊦ i / 2 < j / 2 ↔ ¬ j ≤ i

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 24:
⊦ i ≤ j ↔ ¬ j < i
Proof step 25:
j % 2 = 0, i % 2 = 0, i < 0, j ≤ 0 → (j / 2 < i / 2 ↔ j < i), ¬ j < 0 → (0 < j / 2 + i / 2 ↔ 0 < j + i) ⊦ i / 2 < j / 2 ↔ ¬ j ≤ i

Rule argument

spec: int-abs name: le-def seq: ⊦ i ≤ j ↔ ¬ j < i subst: [j, i] → [j, 0] flags: <all paths>

Additional information

Used terms: j, 0