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Proof step 37 from proof ls-even-01 (previous step)

i % 2 = 0, j % 2 = 0, i / 2 < j / 2, j < 0, j ≤ i, i ≤ 0 → ¬ j < i ⊦

User applied rule case distinction

And obtained the following new goals

Proof step 38:
j % 2 = 0, i % 2 = 0, j < 0, i / 2 < j / 2, j ≤ i ⊦ i ≤ 0

Rule argument

pos: left 6

Additional information

Used simplifier rules: ⊦ i < j ↔ ¬ j ≤ i; (ss)% ⊦ i ≤ j → (j ≤ i ↔ i = j); (s)% ⊦ ¬ i < i; (s)