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Proof step 2 from proof ls-succ (previous step)

0 < i, 0 < j ⊦ i / (j + 1) ≤ i / j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i / j < i / (j + 1), 0 < j, 0 < i ⊦

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)