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Proof step 2 from proof mod-add-zero (previous step)

i % j + j * i1 = 0, 0 < j, 0 ≤ i, 0 ≤ i1 ⊦ i1 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
i % j + j * i1 = 0, 0 < j, 0 < i1, 0 ≤ i ⊦ i1 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i ≠ j → (i ≤ j ↔ i < j); (s)