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Proof step 2 from proof mod-add1-negneg (previous step)

i % j = 0, i < 0, i0 < 0, 0 < j ⊦ (i + i0) % j = i0 % j

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: mod-add-neg: ⊦ i0 % j = 0 ∧ i < 0 ∧ i0 < 0 ∧ 0 < j → (i + i0) % j = i % j;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2