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Proof step 1 from proof mod-add1-posneg-pos (conclusion)
⊦ i % j = 0 ∧ 0 ≤ i + i0 ∧ 0 ≤ i ∧ i0 < 0 ∧ i0 % j ≠ 0 ∧ 0 < j → (i + i0) % j = i0 % j + j
System applied rule normalize
And obtained the following new goals
Proof step 2
:
i % j = 0, i0 < 0, 0 < j, 0 ≤ i + i0, 0 ≤ i ⊦ (i + i0) % j = i0 % j + j, i0 % j = 0
Rule argument
Additional information