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Proof step 11 from proof mod-div-zero (previous step)

j < 0, 0 ≤ j + abs(i) % j ⊦ j = 0, i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
j < 0, 0 ≤ i, 0 ≤ j + i % j ⊦ j = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i < 0 ∧ 0 ≤ j → i < j; (s)%forward-lsle: ⊦ i < j ∧ j ≤ j0 → i < j0; (forward) from specification int-abs%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs% ⊦ i < j ↔ ¬ j ≤ i; (ss)% ⊦ ¬ j < 0 → abs(j) = j; (s)