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Proof step 5 from proof mod-grz-01 (previous step)

0 < i % j, i < 0 ⊦ j = 0, 0 < j ∧ i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
i < 0, 0 < i % j ⊦ j = 0

Rule argument

Additional information

Used simplifier rules: mod-pos-not-neg: ⊦ 0 < i1 ∧ 0 < i % i1 → ¬ i < 0;