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Proof step 2 from proof mod-le-01 (previous step)

0 < j, j ≤ j0, 0 ≤ i ⊦ i % j ≤ j0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: mod-nls-01: ⊦ j ≤ i0 ∧ 0 < j → ¬ i0 < i % j;% ⊦ i ≤ j ↔ ¬ j < i; (ss)