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Proof step 3 from proof mod-le-num (previous step)

1 < i % j, 0 < j0, j < j0, j0 < i % j, 1 < j0, 0 < j, 0 < i % j ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ j ≤ i0 ∧ 0 < j → ¬ i0 < i % j

Rule argument

spec: <toplevel> name: mod-nls-01 seq: ⊦ j ≤ i0 ∧ 0 < j → ¬ i0 < i % j subst: [j, i, i0] → [j, i, j0] flags: <all paths>

Additional information

Used simplifier rules: ⊦ i ≤ j ↔ ¬ j < i; (ss)% ⊦ i < j → ¬ j < i; (s) Used terms: j, i, j0