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Proof step 2 from proof mod-le (previous step)

0 < j, j ≤ j0 + 1, 0 ≤ i ⊦ i % j ≤ j0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: mod-nls-05: ⊦ j ≤ i0 + 1 ∧ 0 < j → ¬ i0 < i % j;%add-c: ⊦ i + j = j + i; from specification int-basic2%add-a: ⊦ i + j + i0 = (i + j) + i0; from specification int-basic2% ⊦ i ≤ j ↔ ¬ j < i; (ss)