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Proof step 13 from proof mod-ls-same-01 (previous step)

0 < i ⊦ i % j < i ↔ abs(j) = 1 ∨ abs(j) ≤ i, i = 0, j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 14:
0 < i ⊦ i % j < i ↔ abs(j) = 1 ∨ abs(j) ≤ i, i = 0, j = 0, j = 1

Rule argument

fma: j = 1

Additional information

Used simplifier rules: mod-one: ⊦ i % 1 = 0; Used formulas: j = 1