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Proof step 3 from proof mod-ls-same-01 (previous step)

⊦ i % j < i ↔ 0 < i ∧ (abs(j) = 1 ∨ abs(j) ≤ i), j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 4:
i < 0 ⊦ i % j < i ↔ 0 < i ∧ (abs(j) = 1 ∨ abs(j) ≤ i), j = 0
Proof step 10:
⊦ i % j < i ↔ 0 < i ∧ (abs(j) = 1 ∨ abs(j) ≤ i), j = 0, i < 0

Rule argument

fma: i < 0

Additional information

Used formulas: i < 0