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Proof step 27 from proof mod-ls-same-02 (previous step)

0 < i % j, i < i % j, 0 ≤ i ⊦ j = 0, j < 0, j ≤ i ∧ 0 < j

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 28:
i < i % j, 0 < i % j, 0 < j, 0 ≤ i ⊦ j ≤ i

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i < j → ¬ j < i; (s)% ⊦ ¬ i < j → (i = j ↔ ¬ j < i); (ss)