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Proof step 3 from proof mod-ls-same-02 (previous step)

⊦ i < i % j ↔ i < 0 ∧ (abs(j) = 1 ∨ abs(j) ≤ abs(i)), j = 0

User applied rule cut formula

And obtained the following new goals

Proof step 4:
i < 0 ⊦ i < i % j ↔ i < 0 ∧ (abs(j) = 1 ∨ abs(j) ≤ abs(i)), j = 0
Proof step 19:
⊦ i < i % j ↔ i < 0 ∧ (abs(j) = 1 ∨ abs(j) ≤ abs(i)), j = 0, i < 0

Rule argument

fma: i < 0

Additional information

Used formulas: i < 0