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Proof step 4 from proof mod-lsz (previous step)

i % j + 1 < j, j + i % j < 0, 0 < j, i % j < ~1, i % j < 0, i < 0 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
i < j, i % j + 1 < j, j + i % j < 0, 0 < j, i % j < ~1, i % j < 0, i < 0, i + 1 < j ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i +1 = i + 1; (s)%trans: ⊦ i < j ∧ j < j0 → i < j0; (forward) from specification int-basic1%lf-01: ⊦ i < j ∧ j < i0 → i +1 < i0; (forward) from specification int-basic1