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Proof step 2 from proof mod-neg-01 (
previous step
)
⊦ ~ i % j = ~(i % j), j = 0
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 3
:
⊦ i % j + ~ i % j = 0, j = 0
Rule argument
Additional information
Used simplifier rules: ⊦ ~ i = j ↔ i + j = 0; (s)