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Proof step 8 from proof mod-next-square (previous step)

⊦ i % 2 = 0, ((i * i) * (i + 1) * (i + 1)) % 4 = 0, i ≤ 0, i % 2 ≠ 1 ∧ 0 < i

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
i % 2 = 1, 0 < i ⊦ ((i * i) * (i + 1) * (i + 1)) % 4 = 0

Rule argument

Additional information

Used simplifier rules: forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward) from specification int-abs% ⊦ i ≤ j ↔ ¬ j < i; (ss)