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Proof step 2 from proof mod-nls-03 (previous step)

i0 < i % j, i ≤ i0, 0 ≤ i0 ⊦ j = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: mod-ls-same-02: j ≠ 0 ⊦ i < i % j ↔ i < 0 ∧ (abs(j) = 1 ∨ abs(j) ≤ abs(i));%mod-grz-01: ⊦ i < 0 ∧ j ≠ 0 → ¬ 0 < i % j;% ⊦ i ≤ ~ j ↔ i + j ≤ 0; (s)% ⊦ i < 0 → abs(i) = ~ i; (s)%forward-le-01: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward) from specification int-abs%forward-lels: ⊦ i ≤ j ∧ j < j0 → i < j0; (forward) from specification int-abs